Files
pangolin/server/migrations/sqlite/000024_invite_rewards.up.sql
T
wangjia 52b5e90d92 fix(server/migrate): 000024 sqlite 重建 subscriptions 后补回 idx_subs_user_exp 索引 + 回归断言
000024 迁移重建 subscriptions 表(source CHECK 扩容)时未重新创建
idx_subs_user_exp(user_id, expires_at)索引,导致 SQLite(生产 pangolin1
实际驱动)上订阅按 user_id/expires_at 查询退化为全表扫描。up/down 均补回
CREATE INDEX,并在 TestSQLiteMigrateUpDown 里加断言防止再次静默丢失。

Co-Authored-By: Claude Sonnet 5 <noreply@anthropic.com>
2026-07-13 07:08:26 +08:00

51 lines
2.0 KiB
SQL

-- users 加两列
ALTER TABLE users ADD COLUMN invite_code TEXT;
ALTER TABLE users ADD COLUMN first_paid_at DATETIME;
CREATE UNIQUE INDEX ux_users_invite_code ON users(invite_code);
-- 邀请关系(一对一绑定)
CREATE TABLE referrals (
id INTEGER PRIMARY KEY AUTOINCREMENT,
inviter_id INTEGER NOT NULL,
invitee_id INTEGER NOT NULL UNIQUE,
device_uuid TEXT,
status TEXT NOT NULL DEFAULT 'bound'
CHECK (status IN ('bound','reg_rewarded','paid_rewarded','rejected')),
reg_rewarded_at DATETIME,
paid_rewarded_at DATETIME,
created_at DATETIME NOT NULL DEFAULT CURRENT_TIMESTAMP,
FOREIGN KEY (inviter_id) REFERENCES users(id),
FOREIGN KEY (invitee_id) REFERENCES users(id)
);
CREATE INDEX ix_referrals_inviter ON referrals(inviter_id, created_at);
-- 通用一次性任务领取
CREATE TABLE reward_claims (
id INTEGER PRIMARY KEY AUTOINCREMENT,
user_id INTEGER NOT NULL,
task_key TEXT NOT NULL,
external_ref TEXT NOT NULL DEFAULT '',
granted_days INTEGER NOT NULL,
granted_at DATETIME NOT NULL DEFAULT CURRENT_TIMESTAMP,
FOREIGN KEY (user_id) REFERENCES users(id)
);
CREATE UNIQUE INDEX ux_claim_user_task ON reward_claims(user_id, task_key);
CREATE UNIQUE INDEX ux_claim_task_ref ON reward_claims(task_key, external_ref);
-- subscriptions.source 扩容(SQLite 需重建表)
CREATE TABLE subscriptions_new (
id INTEGER PRIMARY KEY AUTOINCREMENT,
user_id INTEGER NOT NULL,
plan_id INTEGER NOT NULL,
expires_at DATETIME NOT NULL,
source TEXT NOT NULL CHECK (source IN ('trial','code','pay','invite','task')),
created_at DATETIME NOT NULL DEFAULT CURRENT_TIMESTAMP,
FOREIGN KEY (user_id) REFERENCES users(id),
FOREIGN KEY (plan_id) REFERENCES plans(id)
);
INSERT INTO subscriptions_new (id,user_id,plan_id,expires_at,source,created_at)
SELECT id,user_id,plan_id,expires_at,source,created_at FROM subscriptions;
DROP TABLE subscriptions;
ALTER TABLE subscriptions_new RENAME TO subscriptions;
CREATE INDEX idx_subs_user_exp ON subscriptions (user_id, expires_at);